What is the equation of a circle with its center at 5?

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The circle has a center at (5,5) and a radius of 2. Therefore, the equation is (x-5)2+(y-5)2=22, or (x-5)2+(y-5)2=4.

What is the equation of the circle with a diameter of 12 and a center at (- 2 5 )?

Answer: The equation of a circle that has its center at (2, −5) and has a radius of 12 is (x – 2)2 + (y + 5)2 = 144.

What does HK standard for in the standard circle equation?

The standard form of a circle’s equation is (x-h)² + (y-k)² = r² where (h,k) is the center and r is the radius.

What is the center at the origin contains 0 3?

Center at the origin, contains (0,3) The radius is 3. Point (0,3) is on the circle. This radius is on the x-axis and has length or 3.

How do you find the equation of a circle with center?

The equation of circle with (h,k) center and r radius is given by: (x-h) 2 + (y-k) 2 = r 2. Thus, if we know the coordinates of the center of the circle and its radius as well, we can easily find its equation. Example: Say point (1,2) is the center of the circle and radius is equal to 4

What is the radius of the circle centered at (5 – 2)?

We are centered at (5, −2), which means h = 5 and k = 2. We also know that we have a diameter of 8, which means our radius is 4. We have all of the information we need, so we can now write the equation of this circle.

How to find the radius of a circle in standard form?

Let C(h, k) be the centre of the circle and P(x, y) be any point on the circle. Therefore, the radius of a circle is CP. Let radius be ‘a’. which is called the standard form for the equation of a circle. x2 + 2gx + g2+ y2 + 2fy + f2 = g2 + f2 − c ……………… (1)

What is the circumference of a circle equal to?

The circumference of a circle is equal to 2 (pi) of radius or pi of diameter. The area of a circle is equal to the pi of radius-squared. What is the equation of a circle when the center is at the origin?