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Is X 1/2 the same as X?

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Is X 1/2 the same as X?

No, it’s usually the same as should be written as x^(1/2) to avoid confusion, but (x^1)/2 is indeed the same as x/2 since x^1=x.

How do you do exponentials?

Basic rules for exponentiation

  1. If n is a positive integer and x is any real number, then xn corresponds to repeated multiplication xn=x×x×⋯×x⏟n times.
  2. If we take the product of two exponentials with the same base, we simply add the exponents: xaxb=xa+b.

How do you get rid of Factorials?

Compare the factorials in the numerator and denominator. Expand the larger factorial such that it includes the smaller ones in the sequence. Cancel out the common factors between the numerator and denominator. Simplify further by multiplying or dividing the leftover expressions.

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Can you Exponentiate both sides of an equation?

For Instance: If you wish to solve the equation, , you exponentiate both sides of the equation to solve it as follows: Original equation Exponentiate both sides Inverse property Or you can simply rewrite the logarithmic equation in exponential form to solve (i.e. ).

What is the value of x2-x-1?

x2-x-1=0 Two solutions were found : x = (1-√5)/2=-0.618 x = (1+√5)/2= 1.618 Step by step solution : Step 1 :Trying to factor by splitting the middle term 1.1 Factoring x2-x-1 The

What is the formula to factor X^2-1?

Factor x^2-1. x2 − 1 x 2 – 1. Rewrite 1 1 as 12 1 2. x2 − 12 x 2 – 1 2. Since both terms are perfect squares, factor using the difference of squares formula, a2 −b2 = (a+b)(a−b) a 2 – b 2 = ( a + b) ( a – b) where a = x a = x and b = 1 b = 1. (x+1)(x− 1) ( x + 1) ( x – 1)

How do you solve a x2 + bx + c = 0?

All equations of the form a x 2 + b x + c = 0 can be solved using the quadratic formula: 2 a − b ± b 2 − 4 a c ​ ​. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction. This equation is in standard form: ax^ {2}+bx+c=0.

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How do you prove that x2 = 12?

There’re no x ∈ Q which verifies x2 = 12. Now continue, with 3 instead of two. Since k^2 = 3q^2, k must be divisible by 3. Writing k = 3j, 9j^2 = 3q^2, or 3j^2 = q^2, so q must also be divisible by 3.