How many different committees of 5 members can be formed from 6 men and 4 ladies if each committee is to contain at least one lady?

246
Complete step-by-step answer: According to the question we have to make a committee of 5 and in each committee formed there must be at least one lady. There are 6 gentlemen and 4 ladies. Hence, the required number of committees is 246.

How many ways can a committee of 5 be formed from a pool of 8 people?

So the answer is: there are 6720 ways to pick 5 people from a group of 8 people.

How many property can be held by a group?

So, a group holds five properties simultaneously – i) Closure, ii) Associative, iii) Identity element, iv) Inverse element, v) Commutative.

Is every group of order 4 cyclic?

From Group whose Order equals Order of Element is Cyclic, any group with an element of order 4 is cyclic. From Cyclic Groups of Same Order are Isomorphic, no other groups of order 4 which are not isomorphic to C4 can have an element of order 4.

How many ways can a committee of to be selected from a club with 12 members?

495 ways
Summary: 495 ways a committee of 4 can be selected from a club with 12 members.

How many committees of 5 people can be chosen 10 people?

252 ways
There are 252 ways to select a committee of five members from a group of 10 people.

How many women can be chosen among 7 men in (6C2)?

Such two ‘particular’ women can be chosen in (6C2) = 15 ways. So, three women can be chosen in (16*15) = 240 ways. 5 men can be chosen among 7 men in (7C5) = 21 ways. There are 6 women. Let’s name them as A, B, C, D, E and F. Assume, A and B can’t be in the same committee.

How many women can be on a committee of 5?

“At least” One Women Selected. Which means we have to calculate for the cases when 1 women is on the committee, when 2 women could be on the committee, 3 women on the committee and all 4 women on the committee. A committee of 5 people is to be chosen from a group of 6 men and 4 women.

How many possible combinations are there with 56 men and 15 women?

Well, you can form 8 choose 3 groups of men, and for each of those you can choose any of the 6 choose 2 groups of women. nCr=n!/ ( (r!) (n−r)!) So, 56*15=840 possible combinations, assuming you don’t care about anything other than number of men, number of women.

How many people are required to be on a committee?

A committee of 5 people is to be chosen from a group of 6 men and 4 women. How many committees are possible if there must be “At least “ One women on the committee?