How many different four digit ID tags can be made if it must start with a 7 and no repeats are allowed?

We can fill any of the 8 digits. Consider the fourth place. Here we can fill any 7-digits. Hence the total number of possibilities to arrange the even numbers from 0 to 9 without repetition of any digits =9X9X8X7=4536 ways.

How many different 4 digit pass codes are possible if repetition is not allowed?

To have no repeated digits, all four digits would have to be different, which is selecting without replacement. We could either compute 10 · 9 · 8 · 7, or notice that this is the same as the permutation 10P4 = 5040.

How many different 3 digit identification tags can be made if the first digit must be a 5 and repetitions are not permitted?

There is obviously just the one possible first digit, 5, and then, because that cannot be repeated, 9 possible digits for the second. Since we cannot use either 5 or whatever digit we used for the second, there are only 8 possible digits for the third. There are 9(8)= 72 possible tags.

How many possible 4 digit codes are there?

10,000 possible combinations
There are 10,000 possible combinations that the digits 0-9 can be arranged into to form a four-digit code. Berry analyzed those to find which are the least and most predictable.

How many different 5 digit identification tags can be made if the digits can be used more than once?

How many different ways can a dinner patron select 3 appetizers and 2 vegetables if there are 6 appetizers and 5 vegetables on the menu?

Given, 3 appetizers and 2 vegetables if there are 6 appetizers and 5 vegetables on the menu. Therefore, 200 ways can a dinner patron select 3 appetizers and 2 vegetables from a possible 6 appetizers and 5 vegetables.

How many different combinations are there?

Thus, for the letters, there are 26 possibilities for each of the 3 slots, and for the numbers, there are 10 possibilities for each of the 3 slots. The total number of combinations is then: 26 x 26 x 26 x 10 x 10 x 10 = 17,576,000 ≈ 18 million.

How many digits cannot be repeated in a number system?

(I)Case I: Digits cannot be repeated:If 0 is placed in first place then it becomes a 3-digit number out of 4-places.Thus ,we can fill 1 or 2 or 3 or 4 or 5 or 6 or 7 or 8 or 9 in the first place. Consider the third place.We can fill any of the 8 digits.

How many 3 digit numbers can be arranged with only 5 numbers?

For a number to be even the last digit can only be one of 0,2,4,6,8 that is 5 numbers. The first 3 digits is chosen out of the range 0 to 9. The number of possible 3 digit numbers (without repetition) is given by the formula 9C3 wich is equal to 9!/6! = 504. The first 3 digits can be arranged in 504 ways without repetition.

How many ways can you write a four digit even number?

Hence the digit and unit place can be written in 5 ways. Now the remaining digits can be written in 9,8 and 7 ways respectively (as numbers are not to be repeated). Thus such four digit even number can be written in 5 x 9 x 8 x 7 = 2520 ways, however we are presuming that 0 (Zero) is also considered a valid value on thousands place.

How many possible digits are there in thousands place?

Out of these we need to make 4 digit numbers ie we have 4 places …thousands, hundreds, tens , ones In thousands place out of 10 digits 0 is to be excluded or else the number so formed turns into a 3 digit number. So, 9 possible digits in thousands place. In hundreds place, we can include 0 but already one digit has been placed in ‘thousands’