How many ways are there to select 3 males and 2 females out of 7 males and 5 females?

Out of 7 men, 3 men can be chosen in 7C3 ways and out of 5 women, 2 women can be chosen in 5C2 ways. Hence, the committee can be chosen in 7C3×5C2=350 ways.

How many ways can a team of 5 persons be selected from a group of 4 men and 7 women of the team has at least one man and one women?

21 ways
Hence , there are 21 ways of selecting a team of 5 members from a group of 4 girls and 7 boys, such that there are no girls in the team.

What is the probability that at least one woman selected?

The probability “at least one woman” is selected is 1- 1/28= 27/28.

How many ways are there in selecting 5 members from 6 males and 5 females consisting 3 males and 2 females?

200 ways
(∵ncr=n! r! (n−r)!) Hence in a committee of 5 members selected from 6 men and 5 women consisting 3 men and 2 women is 200 ways.

How many teams of 4 can be selected from a squad of 7?

Hence, a committee of 4 people be selected from a group of 7 people in 35 ways.

How many ways a 6 member team can be formed having 3 men and 3 ladies from a group of 6 men and 7 ladies?

How many ways a 6 member team can be formed having 3 men and 3 ladies from a group of 6 men and 7 ladies? Question 4 Explanation: We have to pick 3 men from 6 available men and 3 ladies from 7 available ladies. Required number of ways = 6C3 * 7C3 = 20 * 35 = 700.

How many ways are there to select a committee of five members of the department if at least one woman must be on the committee?

(a) How many ways are there to select a committee of five members of the de- partment if at least one woman must be on the committee? C(16, 5) − C(9, 5) = 16!

What is the probability of a random team being all female?

There are 10C4 combinations of 4 women to be selected from 10 women. There are 15C4 = 15! / (4! x 11!) = 1365 possible teams. There are 10C4 = 10! / (4! x 6!j = 210 possible 4 woman teams. So probability of a random team being all female is 210 / 1365 = 0.15385 to 5 places. Early symptoms of spinal muscular atrophy may surprise you.

What is the probability that the group will contain 2 men?

The probability that the group will contain 2 men and 2 women is 0.32967. To find the probability that the group will contain at least 1 man and 1 woman, I will consider the complement. The complement is the event where the group contains either all men or all women (This when X = 0 or X = 4).

What is the probability of the fourth selection choosing a woman?

The probability of the fourth selection choosing one of the 7 remaining women from the remaining pool of 13 is: 7/13. The probability of the fifth selection choosing one of the 6 remaining women from the remaining pool of 12 is: 6/12 (or 1/2). The answer is the product of these five probabilities.

How many girls are there in a group?

Example 21 – A group consists of 4 girls and 7 boys. In how many Example 21A group consists of 4 girls and 7 boys. In how many ways can a team of 5 members be selected if the team has no girl?Total number of ways = 4C0 7C5 = 4!/0!(4 0)!