How many times does digit 9 occur?

If we consider all the natural numbers between 1 to 100 then 9 will occur 20 times, Series: 9,19,29,39,49,59,69,79,89,99(10 times in unit digit)

How many times digit 9 will appear in the integers from 1 to 1000?

There are 300 total nines between 1–1000.

How many times does the digit 1 occur between 1 100?

Hence, the digit 1 appears in numbers from \[1\] to \[100\] for 21 times. Hence, the correct answer is D.

How many times does the digit 8 occur between 1 and 100?

19 8’s occur from 1 to 100. 8, 18, 28, 38, 48, 58, 68, 78, 80, 81, 82, 83, 84, 85, 86, 87, 88, 89 and 98.

How many 9s are there between 1 and 99?

There are total 20 nine’s between 1 and 100. 9, 19, 29, 39, 49, 59, 69, 79, 89, 90, 91, 92, 93, 94, 95, 96, 97, 98, 99. you can count total 9 in these series.

How many times does one appear from 1 100?

Hence, the digit 1 appears in numbers from \[1\] to \[100\] for 21 times.

What should be added to make it 1 9?

Step-by-step explanation: we have to add a number to -16/3 to make it 1/9.

How many times does the digit 9 occur between 1 and 999?

From 101 to 899, there are 160 nines. From 900 to 999, there are 100+20=120 nines. Total: 280 nines.

How many times does 9 occur in two digit numbers?

Answer: Based on this, we can deduce that out of 90 total two digit numbers (10–99), 1 is in 10 of them in the first spot (1/9 x 90) and 9 in the second (1/10 x 90). 1 therefore occurs 19 times in numbers 10–99, but only in 18 numbers, as it comes up twice in one number, 11.

How many 9s are there between 1 and 100?

Actually there are 19 distinct numbers but they have asked how 9s comes between 1 and 100. So in 99 we have two 9s. There are total 20 nine’s between 1 and 100. 9, 19, 29, 39, 49, 59, 69, 79, 89, 90, 91, 92, 93, 94, 95, 96, 97, 98, 99. you can count total 9 in these series. From 00 to 99 there are 100 numbers with 2 digits each .

How many times has the digit 9 been used from 1-100?

9,19,29,39,49,59,69,79,89,90,91,92,93,94,95,96,97,98,99. That makes the appearance of the digit 9 from 1 to 100 to 20 times. SORRY FOR THE MESSY SOLUTION , BUT I HOPE YOU WILL UNDERSTAND WHAT I HAVE DONE ! CASE 2: A DOUBLE DIGIT NUMBER HAVING UNIT DIGIT 9 AND DISTRIBUTE ANY NUMBER FROM 0 TO 9 TO THE SECOUND DEGIT

How many 9’s appear exactly 20 times between 1 and 10^2?

Number of times any number is repeated between 1 and 10^n is equal to n× 10^n-1. In this case, we’ve to find the number of 9’s between 1 and 10^2. So here it will be, 2 ×10^2–1 = 2×10=20. Digits from 2 to 9 each appear exactly 20 times between 1 – 100.

How many numbers have 9 in them?

The first number with digit 9 is the single digit number 9. You add 10 to it and the next number with digit 9 in it comes and that is 19. So you keep adding 10 and come to 89 by which time you have 9 numbers which have 9 in them. These numbers are Now the next 10 numbers have one 9 in them except the number 99 which has 2 nines.