When electric flux through a closed surface is negative what type of charge inside it?

The negative flux just equals in magnitude the positive flux, so that the net, or total, electric flux is zero. If a net charge is contained inside a closed surface, the total flux through the surface is proportional to the enclosed charge, positive if it is positive, negative if it is negative.

What can you say about the charge enclosed by the closed surface if flux through it is zero?

Therefore, if a closed surface does not have any charges inside the enclosed volume, then the electric flux through the surface is zero.

What can you say about the flux through a closed surface that encloses an electric dipole?

The electric flux through a closed or Gaussian surface is determined by the net charge within the surface. If the surface encloses a dipole the electric flux through the surface will be zero, as the net charge is zero.

Can the flux through a closed surface be negative?

Flux is negative implies that E and ds are anti-parallel. If net charge present inside that hypothetical surface is negative, then flux is negative. Since flux through the closed surface is negative, according to Gauss’s law, net charge enclosed must be negative.

What is electric flux calculate the flux from a closed surface?

The total of the electric flux out of a closed surface is equal to the charge enclosed divided by the permittivity. The electric flux through an area is defined as the electric field multiplied by the area of the surface projected in a plane perpendicular to the field.

Why is flux through a closed surface zero?

Gauss’s law tells us that the electric flux through a closed surface is proportional to the net charge enclosed by the surface. Thus, the electric flux through the closed surface is zero only when the net charge enclosed by the surface is zero.

How much electric flux emerges out from a closed surface enclosing a charge Q?

In electrostatics total flux linked from the closed surface enclosing the charge is equal to Q/ε0. This is according to Gauss Law. In electrostatics total flux linked from the closed surface enclosing the charge is equal to Q/ε0. This is according to Gauss Law.

Why is electric flux entering a closed surface negative?