Why is the electric field never zero for a dipole?

Originally Answered: Why is the electric field for an electric dipole not zero? Direction of electric field is from positive to negative. Since the difference potential difference between dipole is not zero therefore there is electric field between them.

What will be the electric flux if a dipole is enclosed by a closed surface?

Assertion : If a dipole is enclosed by a surface, then according to Gauss’s law, electric flux linked with it will be zero. Reason : The charge enclosed by a surface is zero.

At what position electric field due to an electric dipole is zero?

Actually the potential due to one charge of the dipole is just equal and opposite to that of due to other charge on any point on the equatorial line,therefore the potential of a dipole vanishes on any point on the equatorial line.

What does it imply about the electric field when the electric potential is zero?

If the electric potential at a certain point is zero, then the electric field at the same point is also zero.

Can electric field at a point be zero?

Yes, electric potential can be zero at a point even when the electric field is not zero at that point. At the midpoint of the charges of the electric dipole, the electric field due to the charges is non zero, but the electric potential is zero.

What is the direction of electric field due to a dipole at a point on a equatorial line?

The direction of electric field at equatorial point A or B will be in opposite direction to that of direction of dipole moment.

What is the direction of net electric field due to an electric dipole at any point on its equatorial line?

For a point on the equatorial line of dipole, the direction of electric, field →E is along a line parallel to the axis of dipole directed opposite to the direction of dipole moment →P.

What is electric dipole derive an expression for torque when dipole is placed in uniform electric field?

τ = (q E sinθ) d = q d E sinθ Since ‘qd’ is the magnitude of dipole moment (p), and the direction of dipole moment is from positive to negative charge; torque is the cross product of dipole moment and electric field.

When an electric dipole is kept in a non uniform electric field it experiences?

If an electric dipole is placed in a nonuniform electric field, then the positive and the negative charges of the dipole will experience a net force. And as one end of the dipole is experiencing a force in one direction and the other end in the opposite direction, so the dipole will have a net torque also.

What is the angle between the electric field and dipole moment of a dipole at a point on its axis?

Hence, the angle between electric field strength and electric dipole moment is 180∘.

Why is there no electric field in dipole dipole?

This is because of the distance between the two consequitive charges due to which a small field is developed. Also if somehow the length of the dipole tends to -»0 , E will also -»0. Simplifying , Electric field is only there if the charges are seprated by some finite distance.

Can the electric field be zero at any given point?

It does not follow that the field is zero at any given point. Gauss’ Law is a statement about electric flux. A nonzero field can have zero flux. The mistake in your reasoning is to conclude that, since the net flux through a closed surface is zero then the electric field everywhere on that surface, and in space, should be zero.

What is the electric flux due to a Gaussian dipole?

Is the TOTAL charge enclosed by the Gaussian surface (The charge inside the closed surface!), not the charge on the surface itself. If you were to meticulously calculate the electric flux due to the dipole through the sphere enclosing it, using the definition of the E-field flux as: you will find the total flux to be 0.

What is the electric field flux through a closed sphere?

So if you have a sphere(closed surface) and you put it in an uniform electric field, then the total flux is 0. However, the Gauss’s law states that the electric field flux through a closed surface equals the enclosed charge divided by the permitivity of free space.