How will you describe the image formed when the object is located at the center of curvature?

When the object is located at the center of curvature, the image will also be located at the center of curvature. In this case, the image will be inverted (i.e., a right side up object results in an upside-down image). The image dimensions are equal to the object dimensions.

How does the focal length of a mirror below relate to the mirror’s radius of curvature?

The distance from the pole to the focal point is called the focal length (f). The focal length of a spherical mirror is then approximately half its radius of curvature. It is important to note up front that this is an approximately true relationship….introduction.

How does the image of an object appear in a convex mirror?

The image produced by a convex mirror is always virtual, and located behind the mirror. When the object is far away from the mirror the image is upright and located at the focal point. As the object approaches the mirror the image also approaches the mirror and grows until its height equals that of the object.

Can you get a real image at any distance of the object from the convex mirror?

Plane mirrors and convex mirrors only produce virtual images. Only a concave mirror is capable of producing a real image and this only occurs if the object is located a distance greater than a focal length from the mirror’s surface.

How do you describe the image formed in a convex mirror if the object is at the center of curvature?

When an object is placed at the center of curvature and focus, the real image is formed at the center of curvature. The size of the image is the same as compared to that of the object.

What is mirror formula also explain linear magnification produced by a concave mirror?

Linear magnification produced by a spherical mirror is the ratio of the size of the image formed by the mirror so that of the size of the object. ⇒ m=OI.

How is focal length calculated?

Focal length = (Object distance / ((1 / Magnification) + 1)) * 1000 , where: Object distance is given in mm; and. Magnification does not have a unit.

What is the formula for calculating the image formed between plane mirrors?

We can find the number of images formed if we know the angle between the plane mirrors. This is given by formula: n= (360/ ϴ) – 1 if 360 /ϴ is even.

What is the formula of convex mirror?

1/f= 1/u + 1/v. This equation is referred to as the mirror formula. The formula holds for both concave and convex mirrors.

What type of image is formed in convex mirror?

virtual and erect
The image formed in a convex mirror is always virtual and erect, whatever be the position of the object.

Can plane mirror form real image?

Yes,a plane mirror can form a real image. A plane mirror can form a real image only for a virtual object. These converging rays of incidents light after reflection intersect at a point to give a real image.

What is mirror formula?

Let’s explore the mirror formula (1/f = 1/v+1/u) and see how to locate images without drawing any ray diagrams.

How do you use the mirror equation in geometry?

Use the mirror equation to deduce that: (a) an object placed between f and 2f of a concave mirror produces a real image beyond 2f . (b) a convex mirror always produces a virtual image independent of the location of the object.

How do you prove a mirror is real?

Use the Mirror Equation to Show that an Object Placed Between F and 2f of a Concave Mirror Produces a Real Image Beyond 2f. – Physics Use the mirror equation to show that an object placed between f and 2f of a concave mirror produces a real image beyond 2f. Hence, the image formed is real.

What is the distance between the two images in the mirror?

The distance between them is 28 cm. A point object is put midway between them on the principle axis of the mirror. Two images of the object are seen in the plane mirror. Find their distances from the plane mirror.

Is the image formed in a plane mirror always behind the mirror?

The image formed in a plane mirror is indeed behind the mirror – how far it is depends on the distance of the object – it’s exactly the same distance. So the question is erroneous. I shall take the liberty of restating it as: “…prove that the image formed in a plane mirror is behind the mirror, equidistant with the object”.