Mixed

What is the end product of the decay of uranium-238?

What is the end product of the decay of uranium-238?

A nucleus of uranium-238 decays by alpha emission to form a daughter nucleus, thorium-234. This thorium, in turn, transforms into protactinium-234, and then undergoes beta-negative decay to produce uranium-234.

When U 238 decays by emitting an alpha particle What is the atomic number of the resulting nucleus What is the resulting atomic mass?

Explanation: Uranium-238 produces thorium-234 by alpha decay. An α-particle is a helium nucleus. It contains 2 protons and 2 neutrons, for a mass number of 4.

What is the energy released in the alpha decay of 238 U?

4.267
Uranium-238

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General
Decay mode Decay energy (MeV)
alpha decay 4.267
Isotopes of uranium Complete table of nuclides

How many alpha and beta decay does u238?

4 α – particles and 2 β particles.

What would happen if uranium-238 undergoes alpha decay and then beta decay?

A nucleus of uranium 238 decays by alpha emission to form a daughter nucleus, thorium 234. This thorium in turn transforms into protactinium 234, and then undergoes beta-negative decay to produce uranium 234. This occurs at the fourteenth generation of the uranium 238 family, when lead 206 is finally produced.

When U 238 decays to the 234 what has been emitted?

Uranium-238 decays by alpha emission into thorium-234, which itself decays by beta emission to protactinium-234, which decays by beta emission to uranium-234, and so on.

What is the nuclear equation for the decay of uranium-238?

An example will show the use of this equation. For the decay reaction 238U → 234Th + 4He, the mass values for 238U and 4He are in Table 3.1; for 234Th it is 234.043 594. Thus we obtain Qα = –931.5 (234.043 594 + 4.002 603 – 238.050 7785) = 4.274 MeV.

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What is the nuclear equation for the alpha decay of uranium 238?

For the decay reaction 238U → 234Th + 4He, the mass values for 238U and 4He are in Table 3.1; for 234Th it is 234.043 594.

What does the 238 in uranium 238 represent?

The atomic number of uranium (see periodic table) is 92, and the mass number of the isotope is given as 238. Therefore, it has 92 protons, 92 electrons, and 238 — 92 : 146 neutrons. When protons, neutrons, and electrons combine to form an atom, some of their mass is converted to energy and is given off.

How many alpha and beta particles are emitted when uranium nuclei 92u 235 decays to 82pb206?

The change in mass is 238 – 206 = 32 unit. It means that 32/4=8α-particles are emitted.

How many alpha and beta particles are emitted when uranium?

8 alpha and 6 beta particles.

Why is beta decay needed in uranium-238?

As a result, beta decay is needed to even up the balance. In the Uranium-238 lineage for example, the first alpha decay is followed by two successive beta decays transforming a thorium 234 nucleus into uranium 234. Alpha decay causes a loss of four nucleons whereas beta decay has no effect on the number of nucleons present.

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How does uranium 238 decay into thorium-234?

It transforms (or decays) into an atom with an atomic number 2 less and a mass number 4 less. Thus, uranium-238 decays through α-particle emission to form thorium-234 according to the equation: “”_92^238″U” →color (white) (l) _90^234″Th” + _2^4″He”

How many protons and neutrons does uranium lose in decay?

Big stuff like Uranium usually undergoes alpha particle decay. An alpha particle is a helium nucleus with 2 protons and 2 neutrons. So that means Uranium is going to lose two protons and 2 neutrons. U-238 has 92 protons and (238-92 = 146 neutrons).

What happens to the nucleus during alpha decay?

During α-decay, an atomic nucleus emits an alpha particle. It transforms (or decays) into an atom with an atomic number 2 less and a mass number 4 less.