When a ball is thrown vertically upwards with velocity 40?
Table of Contents
- 1 When a ball is thrown vertically upwards with velocity 40?
- 2 What will be the velocity of object thrown upwards with after 2 s?
- 3 What is the velocity of the ball after 1 second?
- 4 When a ball is thrown vertically upwards then at the highest point?
- 5 What is the final velocity after time t for upward motion?
When a ball is thrown vertically upwards with velocity 40?
The Correct Answer is Option 3 i.e 60 m. Initial velocity (u) is given as 40 m/s. When a ball is thrown vertically upwards acceleration due to gravity is to be taken negative i.e a = – g = -10 m/s2.
What will be the velocity of object thrown upwards with 40 ms after 2?
So, the final velocity of the ball after 2 seconds will be $20m/s$ will be in the upwards direction. Hence, option B is the correct option. Note: Both velocity and acceleration are vector quantities.
What is the vertical velocity of a ball thrown upward?
Question: A ball thrown vertically upward reaches a maximum height of 30 meters above the surface of Earth. At its maximum height, the speed of the ball is: Answer: 0 m/s. The instantaneous speed of any projectile at its maximum height is zero….Objects Launched Upward.
Variable | Value |
---|---|
v | 0 m/s |
Δy | FIND |
a | -9.8 m/s2 |
t | 0.40 s |
What will be the velocity of object thrown upwards with after 2 s?
Therefore, after 2 seconds the ball is 40.4 m above where it was initially thrown and its vertical velocity at this height is 10.4 m/s.
What is the velocity after 2 seconds?
For example, if a projectile is moving upwards with a velocity of 39.2 m/s at 0 seconds, then its velocity will be 29.4 m/s after 1 second, 19.6 m/s after 2 seconds, 9.8 m/s after 3 seconds, and 0 m/s after 4 seconds.
What is the least velocity at which a ball can be thrown through a distance 40?
5ms−1.
What is the velocity of the ball after 1 second?
After 1 second, the velocity is 4.5+1.5=6 m/s. After 3 seconds, the velocity is 4.5+3×1.5=9 m/s. After t seconds, the velocity is 4.5+1.5t m/s.
What happens when a ball is thrown vertically upwards?
When the body is thrown upwards, it moves up until the velocity of the ball becomes zero and the force exerted on it becomes zero. After that the ball reaches the ground with the acceleration due to gravity with the zero velocity. When the ball goes up, the height of the ball increases and it also moves up.
What happens if a ball is thrown upward?
When you throw an object upwards, it will eventually fall back to the ground under the earth’s gravity. An object that is thrown vertically upwards decelerates under the earth’s gravity. Its speed decreases until it attains a maximum height, where the velocity is zero.
When a ball is thrown vertically upwards then at the highest point?
When a ball thrown vertically upwards it’s velocity is zero but acceleration is non-zero. Acceleration will be equal to ‘g’.
What happens to velocity when a ball is thrown up?
When you throw a ball up in the air, its direction/velocity on the way up, although it rises up into the air, is actually downward. On its way up, its speed decreases, until it momentarily stops at the very top of the ball s motion.
What is the initial velocity of the ball thrown vertically upwards?
A ball is thrown vertically upwards with a velocity of 49 m/s. Calculate (1) The maximum height to which it rises. (2) The total time it takes to return to the surface of the earth. Initial velocity of the ball (u) = 49m/s.
What is the final velocity after time t for upward motion?
Velocity after time t for upward motion is v=u-gt. Velocity v will be zero after 40/9.8 or 200/49 seconds. After that time the ball will start falling down and the velocity after 6 seconds when the ball was thrown up will be 9.8* (6–200/49) which comes out to be 18.8 m/s. This final velocity will be downwards.
How do you find the acceleration of a thrown ball?
Use the formula v = u -gt. This is the first equation of motion and can be derived easily. u = velocity with which the ball was thrown or the initial velocity. g = acceleration due to gravity. I am taking it as 10m/s^2 in the downward direction . So it will be -10. t is obviously time. Putting the values , v= 40 -10.6 = -20m/s.
What is the maximum height to which the ball will rise?
(1) The maximum height to which the ball rises = 122.5 m (2) The total time ball takes to return to the surface of the earth = 5 + 5 = 10 sec. Was this answer helpful?