What is the equation of a line that runs through the point (- 3/5 and has a slope of 2?

ANSWERS: y + 5 = 2(x – 3); y = 2x – 11; and 2x – y = 11.

What is the equation of a line that passes through 0 5?

Since a vertical line has a constant value of x and the line must pass through (0,5) , the equation is x=0 .

What is an equation of the line that passes through the point (- 5 6?

To move from (-5,6), you move down 2 ( a negative direction) and right 5 (a positive direction). This is your slope. Therefore, the equation becomes: (-2/5)X + 4 = y.

Which is an equation of the line that passes through 4 and 6?

Parallel lines have the same slope, so the missing equation must have 14 as its slope. Following the given, substituting 4 as x yields y=6 , so as a shortcut, one can form the equation: 6=14(4)+b to find b .

How do you write the equation of a line in slope-intercept form?

The slope-intercept form is one way to write a linear equation (the equation of a line). The slope-intercept form is written as y = mx+b, where m is the slope and b is the y-intercept (the point where the line crosses the y-axis). It’s usually easy to graph a line using y=mx+b.

What is the equation in slope-intercept form for the line that passes through the points (- 1/3 and (- 2 3?

Answer: The equation of a line passing through the points (-1, 3) and (2, -3) is 2x +y = + 1.

What is the equation of the line passing through 0 5 and has a slope of 3?

Mathematically, it’s that simple! y=mx+b, where m is the slope and b is the y-intercept. y=-3x+b.

What is the equation of a line that passes through the points 0 and 5 and 2 and 2?

The equation of the line that passes through the points (-2, 2) and (0, 5) is y = 3/2 x + 5.

What is an equation of the line that has a slope and passes through the point (- 2 5?

y=1/2x+4. For this problem, you have to a use the slope-intercept line equation, which is y=mx+b, where b is the y-intercept and m is the slope. You solve for b by plugging in the the x, y, and m values. (2,5) is in the form of (x,y) so plug those into the equation along with the slope (m) to get 5=1/2(2)+b.

Which of the following is the equation of a line in slope intercept form?

y = mx + b
The equation of the line is written in the slope-intercept form, which is: y = mx + b, where m represents the slope and b represents the y-intercept.

What is the equation of the line that passes through the point (- 4 2 and has a slope of − 2?

y = 1/2 x + 4 Final answer! We have the point ( -4 , 2 ) so x1 = -4 and y1 = 2. The slope is still 1/2 so m = 1/2.

What is the equation of a line whose slope is 3 and Y intercept is?

we get y=3x−4.

How do you write an equation in slope intercept form?

Writing linear equations using the slope-intercept form. An equation in the slope-intercept form is written as. y=mx+b. Where m is the slope of the line and b is the y-intercept. You can use this equation to write an equation if you know the slope and the y-intercept.

How do you calculate slope in standard form?

To find the slope of a line in standard form, convert the line to slope intercept form. In slope intercept form, y = mx+b, m is the slope.

How do you put equations in standard form?

The standard form of a linear equation is Ax+By=C. To change an equation written in slope-intercept form (y=mx+b) to standard form, you must get the x and y on the same side of the equal sign and the constant on the other side.

How do you convert slope intercept to standard form?

If you have something similar to and you want to convert it to standard form then choose “slope-intercept_to_standard”. Input the equation in standard form x+ y=. or. Enter your equation in slope-intercept form ( form) y=x +. note: make sure you choose the correct form from the drop box above.