What is the gravitational force on it due to the earth at a height equal to half the radius of the earth?

What is the gravitational force on it due to the earth, at a height equal to half the radius of Earth? Acceleration due to gravity on the surface of Earth is 10 m s^(-2). ∴ mass of body, m=64g=6410=6.4kg.

What is weight of that body at a height half of the radius of Earth?

The mass would be half of 5.97*10^24 kg.

What is the value of G on the surface of the earth?

9.8 m/s2
In the first equation above, g is referred to as the acceleration of gravity. Its value is 9.8 m/s2 on Earth. That is to say, the acceleration of gravity on the surface of the earth at sea level is 9.8 m/s2.

What is the weight of an object at the Centre of the earth?

zero
At the center of the earth R is equal to d so the acceleration due to gravity is zero. Since weight of the object is the product of mass and acceleration due to gravity, weight is also zero.

How will weight of a body changes at a height equal to Earth’s radius?

Explanation: The value of gravitational acceleration is (g/4) at height equal to the radius of earth. The value will be (g/16) at the height 3times of the radius of earth .

What is the difference between the fall of a body in the earth’s surface and on the moon’s surface?

The gravity or the puling power of the earth is six times more than that of the moon. So, if a person is weighed on the moon, he will weigh only one-sixth of his weight recorded on the earth. Nevertheless, the moon’s gravity is able to cause tides in the oceans. The earth has about 70 percent of water on its crust.

What is the weight of a 70 kg body on the surface?

So, the weight of a 70 kg body on the given planet will be 40kg.

What is the depth below the surface of the earth?

2×106m.

Why is value of g variable on the surface of Earth?

The variation in apparent gravitational acceleration (g) at different locations on Earth is caused by two things. The distance between the centers of mass of two objects affects the gravitational force between them, so the force of gravity on an object is smaller at the equator compared to the poles.

What is the value of g i on the surface of the earth II at the Centre of the earth?

0
I=GMR2=g=9.8m/s2. For a point at the centre of Earth, g=0, so gravitational intensity at the centre of Earth is zero.

What is the weight of the object at the centre of the earth if the mass is M?

Answer: The weight of a body placed at the centre of the earth is zero. This is because the mass at the exact cenrte of the earth is zero. Gravitational force exists only if there is mass in the object.

Do you weigh more at the center of the earth?

Yes! Your weight would decrease as you moved towards the center of the earth. Only the part of the Earth that’s closer to the center than you are contributes to your weight. At the exact center of the Earth, the gravitational field is actually zero.

How much does a body weigh on the surface of Earth?

A body weighs 63 N on the surface of the earth. What is the gravitational force (in N) on it due to the earth at a height equal to half the radius of the earth? >> A body weighs 63 N on the s… A body weighs 63 N on the surface of the earth.

What is the gravitational force on Earth at R2/4 times the radius?

If u r going R/2times higher R being the radius of earth then the gravitational force will reduce to R2/4 times as it is on raeths surface . There will a small change which may would not be measured without​ any balances​.

What is the value of acceleration due to gravity?

The value of acceleration due to gravity is 9 8 0 c m s − 2. What will be its value if the unit of length is kilometer and that of time is minute? At what height from the surface of the earth will the value of acceleration due to gravity be reduced by 3 6 \% from the value at the surface?

What is the law of universal gravitation?

By Newton’s law of universal gravitation, any two bodies in the universe exert an attractive force on one another (which is equal in magnitude and opposite in direction) whether they are thousands of miles away or thousands of lightyears away. If you’ve taken physics, you might be familiar with the equation F=GMm/r^2.