What is the memory size if a computer has 16 bits for the memory address register and 8 bits for memory buffer register?

The answer is 64 KB. You can address 2^16 words and each word is 8 bit (= 1 byte). Therefore it is 64 KB. If the word size was 16 bit.

What is the used to access 16-bit data in 8086?

What is used to access 16-bit data in 8086? Pipeline architecture. Memory banking is done to access 16-bit data which is stored in two consecutive locations. Hence, memory is divided into two banks: Even Bank and Odd Bank.

How many address lines are required for 1MB memory?

“20” address lines or address bus are required to span “1MB” memory space.

What is the maximum memory size of a microprocessor with a 16-bit address bus?

64 KB
A 16-bit integer can store 216 (or 65,536) distinct values. In an unsigned representation, these values are the integers between 0 and 65,535; using two’s complement, possible values range from −32,768 to 32,767. Hence, a processor with 16-bit memory addresses can directly access 64 KB of byte-addressable memory.

What is a 16-bit system?

16-bit is a computer hardware device or software program capable of transferring 16 bits of data at a time. For example, early computer processors (e.g., 8088 and 80286) were 16-bit processors, meaning they were capable of working with 16-bit binary numbers (decimal number up to 65,535).

How does the 8086 processor identify between 8 bit and 16-bit operations?

The bit size (8-bit, 16-bit, 32-bit) of a microprocecessor is determined by the hardware, specifically the width of the data bus. The Intel 8086 is a 16-bit processor because it can move 16 bits at a time over the data bus. The Intel 8088 is an 8-bit processor even though it has an identical instruction set.

How many address and data lines will be required for following memory systems a 1MB 16 memory system?

For 1M×16 memory chips, how many address lines and data lines are required? – Quora. Since, we know that 1K = 2^10, 1M = 2^20, 1G = 2^30, …. → it means 20 address lines and 16 data lines.

How many bits are required to address 1 MB?

1 MB = 8000000 b. There are 8000000 Bits in a Megabyte.

What is a 16-bit microprocessor?

The 16 bit Microprocessor means that it has 16 address lines. A 16 bit microprocessor is having 16bit register set. It have 16 address and data lines to transfer address and data both. Hence it is 16 address lines. The maximum addresses are 2^16 means 65536.

What is a 16-bit sequence?

How many address lines are there in 8086 microprocessor?

The number of address lines in 8086 is 20, 8086 BIU will send 20bit address, so as to access one of the 1MB memory locations. The four segment registers actually contain the upper 16 bits of the starting addresses of the four memory segments of 64 KB each with which the 8086 is working at that instant of time.

How many 16-bit addresses can be generated by using 16-address lines?

A 16-bits address bus can generate _____addresses. Explanation: By using n-address lines 2^n addresses can be generated. Therefore by using 16- address lines 2^16 = 65,536 addresses can be generated. 1. The register of 8086 are_____ bits in size.

What is the number of bits in the 8086?

Intel 8088 (8 bits according to 1., but 16 bits according to 2. and 3.) Zilog 8000 (16 bits according to 1. and 2., but 32 bits according to 3.) However, the 8086 is a “16-bit CPU” according to all three criteria!

How many segment registers are there in 8086?

The total 1MB Memory of 8086 is divided into 16 segments each of 64KB. There are 4 Segment Registers. 1. Code Segment – A 16 bit Register with the address of that segment (of size 64KB) which contains the processor instructions. The processor uses Code Segment to access instructions referenced by Instruction Pointer.