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How many 5 digit numbers can be made from the digits 1 to 7 if repetition is allowed?

How many 5 digit numbers can be made from the digits 1 to 7 if repetition is allowed?

16807 ways
How many five-digit numbers can be made from the digits 1 to 7 if repetition is allowed? Explanation: 75 = 16807 ways of making the numbers consisting of five digits if repetition is allowed.

How many 5 digit numbers can be formed using the digits 1 to 9 if repetition of digits is not allowed?

The answer is 125. This should be easy if you break it into no digit repeating, one digit repeating and two digits repeating (you cannot have 3 digits repeating in a 5 digit number).

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How many five digit numbers can be formed using only 1 3 5 7 and 9 if repetitions are allowed?

So, possible number of five-digit numbers that can be formed = (5^5) = 3125. So, for these 3125 five-digit numbers, sum of the digits at each place = (3125 / 5) * (1 + 3 + 5 + 7 + 9) = (625 * 25) = 15625.

How many 5 digit numbers can be formed from the integers 1 9?

The answer is 7,560 five-digit numbers.

How many 5 digit numbers can be formed using 0 9 with repetition?

Now, there are 105 ways in which the digits 0-9 can be chosen for the five places of a five digit number. Out of these, 104 start with zero (once we start with 0, there are only 4 slots to fill, where we have 10 choices each).

How many 5 digit numbers can be formed from the integers?

Thanks! The answer is 7,560 five-digit numbers.

How many 5 digit numbers can be formed from the?

Repetition of digits is allowed. ∴ Each place out of unit, 10th, 100th and 1000th can be filled in 5 ways. Total numbers =4×5×5×5×5=2500.

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How many possible 5-digit numbers are there?

The smallest 5 5 -digit number is 10000, 10000, while the largest 5 5 -digit number is 99999. 99999. These 90000 90000 possible 5 5 -digit numbers can have any number from 0 0 to 9 9 in any of the places, except for the placement of zero such that there is no non-zero number to its left.

What is the total number of combinations possible with 5 numbers?

Overall, every one of the 5 places of a 5-digit number can be filled up in ten ways, because it can have 0, 1, 2, 3, 4, 5, 6, 7, 8, or 9. So each of the five places can be similarly filled up in ten ways. Therefore, the total number of combinations possible are 10 × 10 × 10 × 10 × 10 = 1,00,000.

What are digdigits in math?

Digits are the single symbols used to represent numbers in Maths. For example, in number 89, 8 and 9 are two digits. Hence, the numerals such as 0, 1, 2, 3,4, 5,6,7,8,9, and 0 are the form of digits which are used to represent a combination of numbers and do arithmetic operations in our day to day life.

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What is the total number of choices for the first digit?

For the third number, there are 4 choices, for the fourth number there are 3 choices, and for the fifth number there are 2 choices. Thus, the total number of choices is (5) (5) (4) (3) (2) = 600. Alternatively, use the same logic and realize there are 5 choices for the first digit.