How many address lines are needed for 64Kb memory?

Sixteen address lines will address 64K bytes. If you count in binary (which computers always do) and limit yourself to 16 binary columns, you can count from 0 to 65,535. (The colloquial ”64K” is shorthand for the number 66,536.)

How many words memory can accommodate if address space is a 16 bit?

You can address 2^16 words and each word is 8 bit (= 1 byte). Therefore it is 64 KB. If the word size was 16 bit. The answer would be 128 KB.

What is the maximum supported memory size in a 16 bit architecture with 16 bit memory address if each memory address holds 1 byte data?

The microprocessor can access 216=65536 memory addresses, regardless of the size of data held at each memory address. If each memory address holds one byte (8 bits) of data then the total memory size that can be addressed directly is 216 bytes, which is 26 KiB=64 KiB.

What is 64Kb memory?

64 Kb means = 2 ^16 bytes. Addressability concerns the different number of bytes we can point to. So 8 bytes = 2 ^3. If we can address each 8 bytes out of 64Kb, that means= 2^16 / 2^3= 2^13 is your answer.

How many address lines are required to represent 16k memory?

There are 1024 bytes in one k byte. A 16k ram would therefore need 1024*16 = 16384 addresses.

How many address lines are needed for the memory unit 2K * 16?

Correct answer is 31. There will be 11 lines for the address (211=2K), 16 lines for the data, 2 lines for the power supply, and 2 RD and WR lines.

How much memory can 16-bit use?

A 16-bit integer can store 216 (or 65,536) distinct values. In an unsigned representation, these values are the integers between 0 and 65,535; using two’s complement, possible values range from −32,768 to 32,767. Hence, a processor with 16-bit memory addresses can directly access 64 KB of byte-addressable memory.

How can a 16-bit microprocessor generate 20 bit memory addresses?

To generate the 20-bit address, the CPU shifts the segment 4 bits (1 hex digit) to the left and adds the offset to it. A common combination for segment and offset is the CS and IP registers: together they indicate the address of the next instruction.

What is the address space of a system with 16-bit addresses?

On a 16-bit system, the address bus was 24 bits wide, for a physical address space of 16 Mbytes. On a 32-bit system, the address bus was also 32 bits wide, for a physical address space of 4 Gbytes.

What does 16-bit address space mean?

In computer architecture, 16-bit integers, memory addresses, or other data units are those that are 16 bits (2 octets) wide. Since 216 is 65,536, a processor with 16-bit memory addresses can directly access 64 KB (65,536 bytes) of byte-addressable memory.

How many address lines are present on memory chip of 16kb?

What is 16K memory?

16K means 16,384 ‘storage locations’ of 8 bits, thus 16KB. 64 x 16 means 64 storage locations of 16 bits, thus 128 (8 bit) bytes. The example you give for the Atmega is thus 16,384 times 16 (bits) is 32,768 (8 bit) bytes.

How many address lines does a 64k memory have?

So you have 64 Kilobyte memory addressable using 16 address lines. 2 to the power of 16 is 65536, or as we like to write it, 64K. The number of address lines and the bit-length of the address is what determines the number of locations in memory. Maybe you are getting confused with the word size of the CPU?

How many bytes are in a 64 KB address?

Here, 65,536 address locations are provided for a data word, but each data word consists of 8 bits or 1 byte so effectively 65,536bytes sums to 2^16 bytes = 2^6 * 2^10 bytes = 64KB.

How many 16-bit words can be stored in a 64-bit memory?

A 64Kb memory can thus store 32K 16-bit words. But if the CPU’s memory address registers (PC, Stack, MAR etc) are also 16 bits then the addessable memory is 64K locations. If the memory is organised in bytes, that’s 64Kb.

How many bits are in a byte of memory?

A byte is 8 bits and has been since around 1962. So you have 64 Kilobyte memory addressable using 16 address lines. 2 to the power of 16 is 65536, or as we like to write it, 64K. The number of address lines and the bit-length of the address is what determines the number of locations in memory.