What is the maximum and minimum value of x = 2?

To find the maximum and minimum value we need to apply those x values in the original function. To find the maximum value, we have to apply x = 2 in the original function. Therefore the maximum value is 7 at x = 2.

What is the value of x2+y2?

Given x+y=2, so Y= 2-x, substituing (2-x) for y in x²+y² gives the expression: also considered is the fact that a square of a real value is always positive, so the expression x²+y² can be only positive, meaning that the parabola is above X-axis totally.

What is the minimum value of 2^2 + 4^2?

So to find our minimum we can use differentiation. The minimum will occur when the derivative equals 0. Therefore, the minimum value will occur when y = 2 and x = 4. This means the minimum value is 2^2 + 4^2 = 20

How to find the maximum and minimum of a quadratic function?

The maximum or minimum of a quadratic function occurs at x = − b 2a x = – b 2 a. If a a is negative, the maximum value of the function is f (− b 2a) f ( – b 2 a). If a a is positive, the minimum value of the function is f (− b 2a) f ( – b 2 a).

Can a graph have maximum and minimums but not maximums?

So, some graphs can have minimums but not maximums. Likewise, a graph could have maximums but not minimums. Here is the graph for this function. This function has an absolute maximum of eight at x = 2 x = 2 and an absolute minimum of negative eight at x = − 2 x = − 2.

How do you find the maximum and minimum value of parabola?

To find the maximum and minimum value we need to apply those x values in the original function. To find the maximum value, we have to apply x = 2 in the original function. Therefore the maximum value is 7 at x = 2. Now let us check this in the graph. The given function is the equation of parabola.