How do you find the velocity of a projectile before it hits the ground?

If you want to know the velocity of the object at some point before it hits the ground, use the distance the object has fallen at that point in place of the distance to the ground in either equation. Multiply feet per second by 0.68 to find the object’s velocity in miles per hour.

How do you find the time it takes to reach maximum height of a projectile?

Determine how high the projectile traveled above its initial height by using the following formula where V is the initial vertical velocity and T is the time it takes to reach its peak: Height = V * T +1/2 * -32.2 ft/s^2 *T^2 For example, if you had an initial vertical velocity of 32.14 ft/s and a time of one second.

What is the maximum height of a projectile launched with initial velocity?

Note also that the maximum height depends only on the vertical component of the initial velocity, so that any projectile with a 67.6 m/s initial vertical component of velocity will reach a maximum height of 233 m (neglecting air resistance).

What is the vertical velocity of a projectile when it hits the ground?

9.8 m/s/s
The numerical information in both the diagram and the table above illustrate identical points – a projectile has a vertical acceleration of 9.8 m/s/s, downward and no horizontal acceleration. This is to say that the vertical velocity changes by 9.8 m/s each second and the horizontal velocity never changes.

How do you find the initial height of a projectile?

The initial velocity, v0 = 200 ft/sec and the initial height is h0 = 0 (since it is launched from the ground). Formula: h = -16t2 + 200t + 0.

What is the vertical velocity of a projectile?

The numerical information in both the diagram and the table above illustrate identical points – a projectile has a vertical acceleration of 9.8 m/s/s, downward and no horizontal acceleration. This is to say that the vertical velocity changes by 9.8 m/s each second and the horizontal velocity never changes.

What is initial vertical velocity?

The initial vertical velocity is the vertical component of the initial velocity: v 0 y = v 0 sin θ 0 = ( 30.0 m / s ) sin 45 ° = 21.2 m / s .

What is initial velocity formula?

The initial velocity,vi is the velocity of the object before acceleration causes a change. After accelerating for some amount of time, the new velocity is the final velocity, vf. initial velocity = final velocity – (acceleration×time)

What is the distance traveled by a projectile being affected by gravity?

The equation for the distance traveled by a projectile being affected by gravity is sin(2θ)v 2 /g, where θ is the angle, v is the initial velocity and g is acceleration due to gravity. Assuming that v 2 /g is constant, the greatest distance will be when sin(2θ) is at its maximum, which is when 2θ = 90 degrees.

What is the initial velocity of a projectile fired straight up?

A projectile is fired straight upward from ground level with an initial velocity of 128 feet per second. At what instant will it be back at ground level? When will the height be less than 128 feet? The total flight time will be 7.96 s. The projectile will be lower than 128 f t when t < 0.26 s and t > 7.7 s (until it hits the ground).

How do you find the range of a projectile in physics?

1. Launch from the ground (initial height = 0) To find the formula for the range of the projectile, let’s start from the equation of motion. The projectile range is the distance traveled by the object when it returns to the ground (so y=0): 0 = V₀ * t * sin(α) – g * t² / 2.

What is the maximum height a projectile can reach?

Note also that the maximum height depends only on the vertical component of the initial velocity, so that any projectile with a 67.6 m/s initial vertical component of velocity will reach a maximum height of 233 m (neglecting air resistance).